(1) E = Ekin+Epot <0 .
(2) Ekin = kT (k=Boltzmann constant),
whereas the potential energy of the atom of mass m within the cloud with mass M and radius R is given by(3) Epot = -GmM/R (G= gravitational constant).
If one considers the mass M as given, the only variables that determine Ekin and Epot are the temperature T and the radius R of the cloud. These can in principle take on any value that satisfies Eq.(1). However, one can show (virial theorem) that for a system of particles bound by an inverse square law force (like gravitation) the kinetic and potential energy are on the average (or in the state of equilibrium) related by(4) Ekin = - Epot/2 ,
i.e. the total energy(5) E = Epot/2 .
However, for a closed system, the total energy has to be constant (Eq.(1)), and it follows consequently from Eqs.(3) and (5) that the radius R has to be constant as well (at least on average).(6) RE = - GmM/(2E) .
So it is clear from this that the usually given 'Jeans criterion' for gravitational collapse (which relates the mass, radius and temperature of the gas cloud (and is essentially given by Eqs.(2)-(4))) is not a sufficent condition for star formation, because the collapse would soon come to a halt as the temperature and density increases. The second condition for star formation is therefore that the cloud must permanently lose overall energy (i.e. E must become negatively larger for RE to become smaller). This is discussed in more detail in section c) below (which by the way also suggests that the Jeans criterion is actually not a necessary condition for star formation either, as practically any cloud should lose energy at a rate fast enough to lead to a collapse).(7) mv2/r = -GmM(r)/r2 = -Gm2/r2 .4π. 0∫rdr' .r'2n(r') ,
where n(r') is the radial density distribution. Since the condition of an isothermal gas implies that v is independent of r, the left hand side of the equation is proportional to 1/r. This means that the integral on the right hand side must be proportional to r, which requires
(8) n(r') ~ 1/r'2 .
(9) 1/n(r).dP(r)/dr = kT/n(r).dn(r)/dr = -GmM(r)/r2 = -Gm2/r2.4π. 0∫rdr' .r'2n(r') ,
In equilibrium, the density of any isothermal spherical gas cloud will consequently decrease like 1/r2. Any other density distribution can not be stable. If the density decreases slower than 1/r2, the cloud will contract until the equilibrium distribution is reached, if it decreases faster than 1/r2, it will expand accordingly.
For a gas cloud with a density of 100 cm-3, a temperature of 10 oK and an ionization degree of 10-3, the time scale for the energy loss through excitation of high atomic Rydberg states can be estimated to be of the order of 104 years. As this is considerably less than the dynamical time scale for the gas cloud, the latter would practically collapse in free fall. However, as the time scale for elastic collisions is even shorter (about 100 years), energy equilibrium (including the 1/r2 density distribution) is re-established locally. Half of the energy gained during the collapse is therefore turned into thermal energy (Eq.(5)) and the acceleration consequently also halved. As the collisional timescale is inversely proportional to n(r).v(r), it decreases like r3.5 during contraction (the timescale for the excitation of Rydberg states behaves in a similar manner), whereas the dynamical timescale decreases only ~r1.5 (Kepler's law). One can therefore assume that the cloud contracts in sub-sonic free-fall all the way down to solar system dimensions.
In contrast, the assumption of energy loss through excitation of molecules would lead to a cooling time scale about 1 order of magnitude longer in the initial phase and even longer as the cloud contracts (see http://cfa-www.harvard.edu/swas/science1.html). Eventually, molecular cooling would completely cease once the temperature has reached a value which would prohibit the formation of molecules (this should certainly be the case if the energy reaches a few eV, i.e. if R has decreased by a factor 10-3-10-4 (Eq.(3)).
Furthermore, because of the very rapid cooling associated with the excitation of highly excited atomic states, it is in fact the case that practically any gas cloud will become gravitationally unstable as even systems that have positive energy and do not satisfy Eq.(1) will lose their energy excess before they have time to expand and escape their own gravitational field.
In view of these aspects, it seems rather unlikely that molecules have any siginificant influence on the star formation process at all. Molecular clouds could in fact be the result rather than the cause of star formation, because the suggested cooling by excitation of highly excited Rydberg states is likely to be much less effective for molecules (in particular heavier and/or more complex ones) than for atoms, i.e. only for the latter does the cooling and hence the gravitational collapse occur, whereas the molecules are largely left behind.
Of course, once the density has become so high that no individual atoms can exist anymore (which is at a density of the order of n=1023cm-3) the collapse will stop, as no collisional excitation can take place anymore. The only energy loss will then be from the less dense atmosphere, which is too small to lead to a noticeabel contraction, but which explains the low temperature of the solar photosphere in comparison to the temperature to be expected from the gravitational energy of the sun (see the page regarding Coronal Heating).