- #1

- 3

- 0

## Homework Statement

- a ball rolls off an incline on top of a 9.0m building
- at a velocity of 22m/s
- 32° below the horizontal
- how far from the base of the building will the ball hit the ground?
- [ANS = 11m)

## Homework Equations

- vf^2 = vi^2 + 2ad
- d = ((vf+vi)/2)t
- d = vt

## The Attempt at a Solution

- x (um)
- v = 22cos32 = 18.657...m/s

- y (uam)
- a = -9.81m/s^2
- vi = -22sin32 = -11.658...m/s
- d = 9.0m

- vf^2 = vi^2 + 2ad

vf^2 = 312.494...m^2/s^2

vf = 17.677...m/s

- d = ((vf+vi)/2)t

-9.0m = ((17.677...m/s - 11.658...m/s)/2)t

t = ((17.677...m/s - 11.658...m/s)/2) / 9.0m

t = 0.334...s

- d = vt

d = 6.495...m

d = 6.5m

I'm not sure where I made my mistake since I am about 4.5m off.

#### Attachments

Last edited: